kert angle

kert angle
T: R ^ 2 -> R ^ 2 (rotation transformation) Question?

if I turned a vector v in R ^ 2 in the opposite direction at an angle x. then the matrix A is: sin (x)-Sin (x) cos (x) cos (x) 0

Then if I wante to find imT and kerT

then imT = [ 0.2 cos ^ 2 (x)] y Kert = (0.2 cos ^ 2 (x) = 0) = (0, O Pi/2n 3Pi/2n, n is an integer)? Is it just because I'm confused

First, the matrix is ill. Consider: must be the identity matrix x = 0 and it must be a determining factor for all x. The correct answer is A [cos (x)-sin (x)] = [Sen (x) cos (x)]. Now look x Since the matrix of determinant 1, is nonsingular, so its kernel is {(0.0)} T ^ (x independent). And its image is R ^ 2 (independent of x). We know at least 2 different ways. First, since A is invertible, the size of your image is the same order (2), which corresponds to their rank (2). And geometrically pre-image of any vector is all clockwise * x * radians around origin.

john cena vs kurt angle first ever